hello mates
To what temperature a gas at 127°C must be cooled so that its volume is reduced to 1/4
of its initial volume,
pressure remaining constant ?
(-173°C)
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Answer:
It can be solved by using the relation of Charle's Law.
Charle's Law explains that: For a fixed mass of gas at constant pressure (P) ,the volume is directly proportional to the kelvin temperature (T).
Mathematically, At constant P and Mass (or no. of moles = n)
V ∝ T
Or, T1 /T2 = V1 /V2........(1)
Given that:
T1 = 127º C = (273 + 127) = 400 K
T2 = ?
Let V1 be 1 L
V2 would be 1/4 L
Using equation 1)
T2 = V2/V1 x T1
= 1/4 x 400 K
= 100 K
So the temperature should be reduced to 100 K to get the 1/4 of initial volume of gas.
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