Question

Hello ! Pls solve the above sum. Thank you. No spamming. pls dont spam.​

Answer 1

Answer:

{(3)²-(2)³}÷(4)²

[9-8]÷16

1÷16

1/16

Answer 2

Answer:

Question:-

simplify

$({ \frac{1}{3} }^{ - 2} - { \frac{1}{2} }^{ - 3} ) \div { \frac{1}{4} }^{ - 2}$

Answer:-

$\frac{ {1}^{ - 2} }{ {3}^{ - 2} } - \frac{ {1}^{ - 3} }{ {2}^{ - 3 } } \div \frac{ {1}^{ - 2} }{ {4}^{ - 2} }$

$(\frac{1}{9} - \frac{ - 1}{ - 8}) \div \frac{1}{16}$

$( \frac{8}{72} - \frac{9}{72} ) \div \frac{1}{16}$

$( \frac{ - 1}{72} ) \div \frac{1}{16}$

$\frac{ - 1}{72} \times 16$

$\frac{ - 1}{9} \times 2$

$\frac{ - 2}{9}$

hope it helps

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