help in 3,4,5,6 questions
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Answers
4)base=X
height=1/X
area of parellelogram
Answer:
(3) Here,
length of AD = 49cm
length of AB = 35 cm
area of parallelogram ABCD = 1470 cm²
area of Parallelogram ABCD = length of AD × length of BE = length of AB × length of DF
so, area of ABCD = 1470 = length of AD × length of BE
=> 1470 = 49 × length of BE
length of BE = 1470/49 = 30 cm
similarly, area of ABCD = 1470 = length of AB × length of DF
=> 1470 = 35 × length of DF
length of DF = 1470/35 = 42 cm
hence, BE = 30cm and DF = 42cm
(4) Let the base be x
Then height = x/3
Area of llgm= 108cm²
b×h= 108cm²
x*x/3= 108
x²= 108*3
x= √324
x= 18cm
Base of parallogram= 18cm
Height of the parallogram = x/3
= 18/3
= 6cm
(5)area of parallellogram= base x height
= 5x X 2x
=10x^2
10x^2=360m^2
x^2= 36
x= 6
base= 5 x 6=30m
height= 2x6= 12m
(6)Let b be the base of the parallelogram, then the area of the parallelogram is equal to 2(0.5 × 20 × 2b) = 1600
Then:
2(10 × 2b) = 1600
⇔ 20 × 4b = 1600
⇔ 4b = 1600/20
⇔ 4b = 80
⇔ b = 80/4
⇔ b = 20 m
Hence, the length is 20 m.
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