Question

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The number of atoms present in 0.1 mole of P4 (atomic mass 31) are
A) 2.41024 atoms B) Same as in 0.05 mol of S8
C) 61022 atoms D) Same as in 3.1 g of phosphorous

Answer 1

Atomic mass of P is 31 g/mol

Then melcular mass of P4 i.e, will be equal to 4 atoms of P.

Since we know that,

1 mole of P = 6.022 × 10²³

0.1 mole of P = 6.022 × 0.1 × 10²³

0.1 mole of P = 0.6022 × 10²³

0.1 mole of P = 6.022 × 10²²

Now, 0.1 mole of P4 i.e, 4 atoms of P = 4 × 6.022 × 10²²

0.1 mole of P4 = 24.088 × 10²²

0.1 mole of P4 = 2.4088 × 10²³

0.1 mole of P4 = 2.41 × 10²³