Question

help me out guys...12th​

Answer 1

the first positive integer divisible by 6 is 6

" second " " 12.

the 40th ". " by 6 is 240.

then,. the A.P. is 6,12,18.......240.

S40 = 40/2(a+l)

= 20 ( 6+240)

= 246*20

= 4920. ans

Answer 2

Answer:Hope you've been helped.

Plzz mark me as brainliest....   : )

Step-by-step explanation:

If we multiply 1 with 6, we'll get first integer of 6. We'll get 2nd integer by multiplying 2 with 6 and so on....

So, Sum of first 40 integers of 6 is:

(6×1)+(6×2)+......+(6×40)

=6(1+2+.....+40)

=6{40/2(40+1)}        [As, the sum of first n numbers is= {n/2(n+1)}]

=6(20×41)

=6×820

=4920