Question

Help me please. I don't have any idea
An engineer working for a manufacturer of electronic components
takes a large number of measurements of a particular dimension of
components from the production line. She finds that the distribution
of dimensions is normal, with a mean of 2.340 cm and a coefficient
of variation of 2.4%.
a) What percentage of measurements will be less than 2.45 cm?
b) What percentage of dimensions will be between 2.25 cm and 2.45
cm?
c) What value of the dimension will be exceeded by 98% of the
components?

Answer 1

Answer:

Step-by-step explanation:

Given- The probability that a river flow exceeds 2,000 cubic meters per second is 15% i.e. P(X > 2,000) = 0.15 According to normal distribution; Z values = (X-μ)/? Hence, P[Z> 2,000 -μ/?] = 0.15 => (2,000 -μ)/?= 0.15 =>2,000 -μ= 0.15*? .(1) CV = (?/μ)*100 = 20% =>?/μ = 0.2 =>?= 0.2*μ .(2) a) The mean of the flow is1,941.75 Putting the value of ? from equation(2) inequation (1); we get- =>2,000 -μ= 0.15*0.2 * μ => 2,000 = 0.03μ +μ =>μ = 2,000/ 1.03 => μ = 1,941.75...