Question

Help me with this question

Answer 1

Given :-

• Coordinates of A = (-2 , -2 )
• Coordinates of B = ( 2, -4 )
• AP = 3/7AB or 3/7×AB

To Find :-

• Coordinates of P

Formula :-

• To find the distance between two points or coordinates is √(x1 - x2) ² + (y1 - y2 )²

Solution :-

Let the distance between coordinate of A and coordinate of B be - AB

Let the distance between coordinate of A and coordinate of P be - AP

Let here x1 be -2( 1st point of coordinate of A)

Let here x2 be 2(1st point of coordinate of B)

Let y1 here be -2 (Second point of coordinate of B)

Let y2 here be -4 (First point of coordinate of A)

Let the coordinates of P be ( x, y)

AB = √( x1 - x2 )² + ( y1 - y2 )²

=> AB = √(-2 - 2) ² + ( - 2 - (-4) ) ²

=> AB = √(- 4 )² + ( - 2 + 4 ) ²

=> AB = √ 16 + (2)²

=> AB = √ 16 + 4

=> AB = √20

Therefore, AB = 2√5 .

Now, according to the question the condition is :-

AP = 3/7 × 2√5

=> AP = 6√5 / 7

Now, here x1 = - 2 (

Now, here x2 =

Now, here y1 =

Now, here y2 =

Answer 2

Answer:

Given :-

Coordinates of A = (-2 , -2 )

Coordinates of B = ( 2, -4 )

AP = 3/7AB or 3/7×AB

To Find :-

Coordinates of P

Formula :-

To find the distance between two points or coordinates is √(x1 - x2) ² + (y1 - y2 )²

Solution :-

Let the distance between coordinate of A and coordinate of B be - AB

Let the distance between coordinate of A and coordinate of P be - AP

Let here x1 be -2( 1st point of coordinate of A)

Let here x2 be 2(1st point of coordinate of B)

Let y1 here be -2 (Second point of coordinate of B)

Let y2 here be -4 (First point of coordinate of A)

Let the coordinates of P be ( x, y)

AB = √( x1 - x2 )² + ( y1 - y2 )²

=> AB = √(-2 - 2) ² + ( - 2 - (-4) ) ²

=> AB = √(- 4 )² + ( - 2 + 4 ) ²

=> AB = √ 16 + (2)²

=> AB = √ 16 + 4

=> AB = √20

Therefore, AB = 2√5 .

Now, according to the question the condition is :-

AP = 3/7 × 2√5

=> AP = 6√5 / 7