Help meee I will marks it as the brainliest
Currently, it's 1 m.
So, we need a lens that creates an image of an object placed 1/4 m away from it at 1 m.
So, using lens formula, and v = -1 m, u = -1/4 m, we get 1 / f = Power = 3 m^(-1) = 3 D.
The scattering depends inversely on the wavelength (some power of it, I don't remember), so, for lesser wavelength, there's more scattering.
Blue has less wavelength than red, green, etc, so it is scattered more - throughout the sky, and we get a blue-colored thingamajig.
Net resistance here would be: (rho1)L/A + (rho2)L/A = (rho1 + rho2)L/A.
Let equivalent resistivity be rhoE.
So, rhoE(2L)/A = (rho1 + rho2)L/A.
And, rhoE = (rho1 + rho2)/2
Answers
here your answer dear......
1)1D
2) refraction
3)p1+p2/2
Answer:
Explanation:
Answers: 1. (1) 3D, 2. (3) Scattering (Rayleigh), 3. (1) Average of the two.
1. Normal distance of distinct vision = 25 cm = 1/4 m.
Currently, it's 1 m.
So, we need a lens that creates an image of an object placed 1/4 m away from it at 1 m.
So, using lens formula, and v = -1 m, u = -1/4 m, we get 1 / f = Power = 3 m^(-1) = 3 D.
2. Rayleigh scattering. Fact.
The scattering depends inversely on the wavelength (some power of it, I don't remember), so, for lesser wavelength, there's more scattering.
Blue has less wavelength than red, green, etc, so it is scattered more - throughout the sky, and we get a blue-colored thingamajig.
3. Resistance = (rho)L/A.
Net resistance here would be: (rho1)L/A + (rho2)L/A = (rho1 + rho2)L/A.
Let equivalent resistivity be rhoE.
So, rhoE(2L)/A = (rho1 + rho2)L/A.
And, rhoE = (rho1 + rho2)/2