Question

help needed for the question

Answer 1

Hi mate.


Thanks for asking this question.



Here is your answer,



#

When we consider the conjugation,

hyper conjunction and hydrogen bonding. The

order becomes,


B > D > A > C.



The enol that formed in case of option

B have a substituted double bonds ( which

simply means that, this is more

hyperconjugative structure ) as compared to

the other options.



Both the options A and C having a lack of

hydrogen bonding.




Thank you.





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