Math, asked by UrvashiBaliyan, 11 months ago

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Answered by rahman786khalilu
1

Answer:

hope it helps you ! mark as brainliest

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Answered by smartyrathore
0

 3x-2÷(X+1)^2*(x+3)=(3x-2)÷

(X+1)(X+1)(X+3)

=A/(X+1) +B/(X+1) +c/(X+3)

(3x-2)=(Ax^2+4Ax+3A)+(Bx^2+

4Bx+3B)+(Cx^2+2Cx+C)

(3x-2)=x^2(A+B+C)+X(4A+4B+

2C)+(3A+3B+C)

A+B+C=0---------------------equation(1)

4A+4B+2C=3--------------equation(2)

3A+3B+C=-2------------- equation(3)

equation 2- 4×equation(1)---

-2C=3

c=-3/2

equation2 - equation (3)-----

A+B+C=5---------------equation(4)

equation 2- equation 1×2---------

2A+2B=3---------equation(5)

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