Question

help solving this !!!!!!!!!!!!!!!!!

Answer 1

$\sqrt[ 3]{2 } = {x}^{ \frac{1}{12} } \\ = > 2 = {x}^{ \frac{1}{12} \times 3 } \\ = > 2 = {x}^{ \frac{1}{4} } \\ = > {2}^{4} = x \\ = > x = 16 \\ \\ formulas \: used \\ 1.\: \sqrt[n]{a} = {a}^{ \frac{1}{n} }$