Math, asked by maddieschuyler, 1 year ago

HELP WITH THIS QUESTION ASAP!! I need to raise my geometry grade!

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Answers

Answered by Anonymous
3
\huge \boxed {Hello}

Given, length of diagonal, d =
6 \sqrt{3}
We know that, Perimeter P

= 2 \sqrt{2} d

= 2 \times 6 \sqrt{3 \times 2} = 12 \sqrt{3 \times 2} = 12 \sqrt{6} in

We also know that, Area of a square, A

= 1/2 d^2

= 54 in^2

Hence, second option is correct!
Answered by Anonymous
3
Given, length of diagonal, d =
6 \sqrt{3}63​ 
We know that, Perimeter P

= 2 \sqrt{2} d22​d 

= 2 \times 6 \sqrt{3 \times 2} = 12 \sqrt{3 \times 2} = 12 \sqrt{6}2×63×2​=123×2​=126​ in

We also know that, Area of a square, A

= 1/2 d^2

= 54 in^2

Hence, second option is correct!
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