Question

Hey

Answer

Needed With Full explanation

#No Spamming

#Surya...

Answer 1

Heya,

Let the cost of full and half first class fare be Rs. x and Rs. x/2 respectively and reservation charges be Rs. y per ticket.

CASE 1

The cost of one reserved first class ticket
from stations A to B,

= Rs. 2530

x + y = 2530 ( i )

CASE 2

The cost of one reserved first class ticket and one reserved first class half ticket from stations A to B = Rs. 3810

x + y + x/2 + y = 3810

3x/2 + 2y = 3810 , 3x + 4y = 7620 ( ii )


Now, multiplying equation ( i ) by 4 and then subtracting from equation ( ii ) , we get

( 3x + 4y ) - ( 3x + 4y ) = 7620 - 10120 - x = -2500

x = 2500

On putting the value of x in equation ( i ) we get,

2500 + y = 2530

y = 30

Hence, full first class fare from stations A to B is Rs. 2500 and the reservation for a ticket is Rs. 30.....

Hope this will help you ! : )

Answer 2

$\huge \mathcal {\fcolorbox{red}{gray}{\green{A}\pink{N}\orange{S}\purple{W}\red{E}\blue{R}{!}}}$

The cost of one reserved first class ticket

from stations A to B,

= Rs. 2530

x + y = 2530 ( i )

CASE 2

The cost of one reserved first class ticket and one reserved first class half ticket from stations A to B = Rs. 3810

x + y + x/2 + y = 3810

3x/2 + 2y = 3810 , 3x + 4y = 7620 ( ii )

Now, multiplying equation ( i ) by 4 and then subtracting from equation ( ii ) , we get

( 3x + 4y ) - ( 3x + 4y ) = 7620 - 10120 - x = -2500

x = 2500

On putting the value of x in equation ( i ) we get,

2500 + y = 2530

y = 30

Hence, full first class fare from stations A to B is Rs. 2500 and the reservation for a ticket is Rs. 30.....

HOPE SO IT WILL HELP.....