Question

hey can someone help me with this sum I'll mark the person as a brainliest

Answer 1

$\mathbb{\huge{\red{\boxed{MasterJi}}}}$
through the converse mid point their

PQ||BC and PQ=1/2BC

NOW, BC=11 SO PQ =5.5

so area of trapezium = area(∆ABC)-area(∆APQ)

find them using heron's formula here is you answer

Answer 2

Answer:

26.4 cm

Step-by-step explanation:

Given, AB = 9.6 cm, BC = 11 cm, AC = 10.2 cm.

From figure:

(i)

P is the mid-point of AB.{AP = PB}

⇒ AP + PB = 9.6

⇒ PB + PB = 9.6

⇒ 2PB = 9.6

⇒ PB = 4.8 cm

(ii)

Q is the mid-point of AC.

⇒ AQ + QC = 10.2 cm

⇒ QC + QC = 10.2

⇒ 2QC = 10.2

⇒ QC = 5.1 cm

∴ Perimeter of PBCQ

= 4.8 + 11 + 5.1 + 5.5

= 26.4 cm.

Therefore, Perimeter of PBCQ = 26.4 cm.

Hope it helps!