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Atomic mass of Fe = 56 g/mol
atomic mass of S = 32 g/mol
molar mass of 7H2O = 7 × { 2 ×1 + 16 } =126 g/mol
now,
% of water in FeSO.7H2O ={ molar mass of 7H2O /molar mass of FeSO4.7H2O }× 100
= { 126/278} × 100
= 12600/278
= 45.32 %
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atomic mass of S = 32 g/mol
molar mass of 7H2O = 7 × { 2 ×1 + 16 } =126 g/mol
now,
% of water in FeSO.7H2O ={ molar mass of 7H2O /molar mass of FeSO4.7H2O }× 100
= { 126/278} × 100
= 12600/278
= 45.32 %
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Plz Mark Me As Brainlist
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