Question

Hey Guys! a quēst For all of you!♡

A cat saw a rat when it was exactly at the middle of a
vertical tower. At that moment the angle of elevetion
as observed by the cat was 30°. The cat ran a certain
distance towards the tower to chose the rat, which
then an to the top of the tower. If the cat, which is now
20 m away from the foot of the tower, finds the angle
of elevation of the rat to be 60°, what distance cat run?
Kindly don't spam and give proper explanation! :)​

Answer 1

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Answer 2

Answer :

$\bf \theta = 30$

Step by Step Explanation :

Consider the :

The angle made by the foot of the Ladder on the ground as -

$\sf \implies \theta \: Degree$

As we know :

Ladder = 2

i.e. AC = 2 AB

Now, In

$\triangle \sf \: ABC,$

$\sf \implies \dfrac{AB}{AC} = sin \: \theta$

$\sf \implies \: \dfrac{AB}{2AB} = \sin \theta = \dfrac{1}{2}$

$\sf \implies \theta \: = 30$

We got the answer :)