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Here is the answer =>
Step-by-step explanation:
Equation =>x+3y-k=0
Values=>x=2,y=-1.
=>x+3y-k=0
=>(2)+3(-1)-k=0 (Putting the values).
=>2-3-k=0
=>-1-k=0
=>-k=1
=>k=-1
VERIFICATION =>
=>x+3y-k=0
=>(2)+3(-1)-(-1)=0
=>2-3+1=0
=>-1+1=0
=>0=0
LHS =RHS.
Hence verified.
So the value of k is 1 for x=2 and y=-1 in the equation x+3y-k=0.
HOPE IT HELPS.
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