Question

hey guys help me it's urgent .....​

Answer 1

Given that :

${x}^{2} + \frac{1}{ {x}^{2} } = 62$

Now,

${(x + \frac{1}{x}) }^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2x \times \frac{1}{x} \\ \\ = > {(x + \frac{1}{ {x}^{2} } )}^{2} = 62 + 2 \\ \\ = > {(x + \frac{1}{x} )}^{2} = 64 \\ \\ = > x + \frac{1}{x} = 8$

I hope it will be helpful for you

Mark it as brainliest and

Fóllòw MË ☺️☺️

Answer 2

$\huge\boxed{\fcolorbox{cyan}{red}{Solution:-}}$.

➡Given here.

♠X² + X²= 62.......(1)

➡Find Here,

♠X +1/X = ?.

➡We know.

♠(a+b)²=a²+b²+2ab.

So,

=> (x+1/x)²

= (x² + 1/x² + 2).

= (62+2). [by (1).]

= 64.

➡(x+1/x)= √64.

=±8.

➡Hopes its helps u.

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