Question

hey guys plz solve this sum from indices

Answer 1

${2}^{3x + 4} = {2}^{3x + 2} + 96 \\ {2}^{3x } \times {2}^{ 4} = {2}^{3x } \times {2}^{2} + 96 \\ 16 \times {2}^{3x } - 4 \times {2}^{3x } = 96 \\ 12 \times {2}^{3x } = 96 \\ {2}^{3x } = 8 = {2}^{3} \\ therefore \: \: 3x = 3 \\ x = 1$