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Hey !!!
x = 2⅓ + 2⅔ ( given )
(2^ ⅓ + ⅔ )
from given question
x³ - 6x
(2⅓+2 ⅔)³ - 6 (2⅓+ 2⅔)
using formula .
•°• ( a + b) ³ = a³ + b³ + 3ab ( a + b ) .
2 ^3/3 + 2^6/3 + 3×2⅓× 2⅔ ( 2 ⅓ + 2⅔) - 6 (2⅓ + 2⅔)
using rule a^m × a^n = a^(m+n)
=> 2 + 2² + 3×2^3/3 (2⅓+ 2⅔)- 6 (2⅓ + 2⅔)
=> 6 + 6(2½ + 2⅔) - 6(2⅓+ ⅔)
=> 6 prooved ♻ lhs = Rhs
_____________________
Hope it helps you !!!
@Rajukumar111
x = 2⅓ + 2⅔ ( given )
(2^ ⅓ + ⅔ )
from given question
x³ - 6x
(2⅓+2 ⅔)³ - 6 (2⅓+ 2⅔)
using formula .
•°• ( a + b) ³ = a³ + b³ + 3ab ( a + b ) .
2 ^3/3 + 2^6/3 + 3×2⅓× 2⅔ ( 2 ⅓ + 2⅔) - 6 (2⅓ + 2⅔)
using rule a^m × a^n = a^(m+n)
=> 2 + 2² + 3×2^3/3 (2⅓+ 2⅔)- 6 (2⅓ + 2⅔)
=> 6 + 6(2½ + 2⅔) - 6(2⅓+ ⅔)
=> 6 prooved ♻ lhs = Rhs
_____________________
Hope it helps you !!!
@Rajukumar111
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