Hey mate
plss solve my questions...
solve questionsss.
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Question no. 25
Volume of cuboid= lbh {cubic unit}
So, given volume of the godown=
(50×30×20)m^3
= 30000m^3
Now, cuboidal box can stored each = 0.3m^3
So, no. of boxes which can stored= 30000m^3/0.3m^3
= 100000 boxes. Answer✓✓
____________________________________
Ques. No. 26
A cuboidal tank contain= 60000Litres
Given, Length= 10m, breadth= 3m
And let height be d m
Capacity of tank= 60000litres
Volume of Cuboid= 6000litres
So, lbh= 60000litres
= 10m×3m×dm= 60000litres
= 30d m^3= 60000×1/1000m^3{1m^3= 1000litres, 1litres = 1/1000m^3}
= 30dm^3= 60m^3
= d= 60÷30
= depth= 2m answer✓✓
____________________________________
Ques.27-
Given, A rectangular plot of length and breadth = 60m and 34m
Let height be x.
And volume of the mud pit = 510m^3
Now, Volume of cuboid= lbh{cubic unit}
= 60m×34m×xm= 510m^3
= 2040xm^3=510m^3
= x= 510m^3/2040m^2
= x= 0.25m height answer.✓✓✓
____________________________________
Ques.28_
Given,
Length= 4m
breadth=2m
Height= 7m
Now, Volume of Cuboidal pit= lbh
= 4m×2m×7m= 56m^3
Cost of digging 1m^3= Rs.45
Cost of Digging 56m^3= (56×45)Rs.
= Rs. 2520 answer✓✓✓✓
____________________________________
Question No.31
Given,
Length= 15m
Breadth=7m
Height= 8m
Now, Surface area of Cuboidal tiffin box =
2(lb+bh+lh)sq. unit
= 2(15m×7m+7m×8m+15m×8m)Sq. unit
= 2(105m^2+56m^2+120m^2)Sq.unit
=2(281)m^2
= 562m^2 Answer.✓✓✓✓
____________________________________
Question no.30
The capacity of tank is 5m×4m×6m= 120m^3
]6m Is the height of water tank}
[We know that 1m^3= 1000litres and 1l=0.001m^3]
So, 2000litres= 2m^3
Now, Find the water of the height_
Volume= lbh
=2m^3= 5m×4m×h
=2m^3= 20m^2h
= h= 20m^2/2m^3
= h= 10m Answer.✓✓✓
Question no. 25
Volume of cuboid= lbh {cubic unit}
So, given volume of the godown=
(50×30×20)m^3
= 30000m^3
Now, cuboidal box can stored each = 0.3m^3
So, no. of boxes which can stored= 30000m^3/0.3m^3
= 100000 boxes. Answer✓✓
____________________________________
Ques. No. 26
A cuboidal tank contain= 60000Litres
Given, Length= 10m, breadth= 3m
And let height be d m
Capacity of tank= 60000litres
Volume of Cuboid= 6000litres
So, lbh= 60000litres
= 10m×3m×dm= 60000litres
= 30d m^3= 60000×1/1000m^3{1m^3= 1000litres, 1litres = 1/1000m^3}
= 30dm^3= 60m^3
= d= 60÷30
= depth= 2m answer✓✓
____________________________________
Ques.27-
Given, A rectangular plot of length and breadth = 60m and 34m
Let height be x.
And volume of the mud pit = 510m^3
Now, Volume of cuboid= lbh{cubic unit}
= 60m×34m×xm= 510m^3
= 2040xm^3=510m^3
= x= 510m^3/2040m^2
= x= 0.25m height answer.✓✓✓
____________________________________
Ques.28_
Given,
Length= 4m
breadth=2m
Height= 7m
Now, Volume of Cuboidal pit= lbh
= 4m×2m×7m= 56m^3
Cost of digging 1m^3= Rs.45
Cost of Digging 56m^3= (56×45)Rs.
= Rs. 2520 answer✓✓✓✓
____________________________________
Question No.31
Given,
Length= 15m
Breadth=7m
Height= 8m
Now, Surface area of Cuboidal tiffin box =
2(lb+bh+lh)sq. unit
= 2(15m×7m+7m×8m+15m×8m)Sq. unit
= 2(105m^2+56m^2+120m^2)Sq.unit
=2(281)m^2
= 562m^2 Answer.✓✓✓✓
____________________________________
Question no.30
The capacity of tank is 5m×4m×6m= 120m^3
]6m Is the height of water tank}
[We know that 1m^3= 1000litres and 1l=0.001m^3]
So, 2000litres= 2m^3
Now, Find the water of the height_
Volume= lbh
=2m^3= 5m×4m×h
=2m^3= 20m^2h
= h= 20m^2/2m^3
= h= 10m Answer.✓✓✓
riyasharma37:
thanqqq so much
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