Hey mates please answer this question two isosceles triangles have equal vertical angles and their areas are in the ratio 9:16. Find the ratio of their corresponding heights
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Answered by
1
As the triangles have equal vertical angle,So the other two angles are also same.
So both triangles are similar.
We know that
for two similar triangles the ratio of the areas are equal to the ratio of the squares of the corresponding sides (or ratio of corresponding heights)
So ratio of sides=3/4=ratio of corresponding height.
So both triangles are similar.
We know that
for two similar triangles the ratio of the areas are equal to the ratio of the squares of the corresponding sides (or ratio of corresponding heights)
So ratio of sides=3/4=ratio of corresponding height.
Answered by
3
Given ABC and DEF are isosceles triangles and AP and DQ are their respective altitudes or heights.
In ΔABC, AB = AC
In ΔDEF, DE = DF
Also ∠A = ∠D
Hence by SAS similarity criterion ΔABC ~ ΔDEF
AP:DQ = √3 : √2
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