hey need answer fast the best ans will be BRAINLIEST
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Answer:
(x + y + z)[x² + y² + z² - xy - yz - zx]
Step-by-step explanation:
Given Equation is x³ + y³ + z³ - 3xy
It can be written as,
= x³ + y³ + z³ + 3x²y - 3x²y + 3xy² - 3xy² - 3xy
Rearrange the terms
= x³ + y³ + 3x²y + 3xy² + z³ - 3xyz - 3x²y - 3xy²
= (x + y)³ + z³ - 3xyz - 3x²y - 3xy²
= (x + y)³ + z³ - 3xy(x + y + z)
= (x + y + z)[(x + y)² + z² - (x + y)z] - 3xy(x + y + z)
= (x + y + z)[x² + y² + 2xy + z² - xz - yz - 3xy]
= (x + y + z)[x² + y² + z² - xy - yz - zx]
Hope it helps!
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