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Answers
We are given that the streamer covers same distance between two places but it takes 5 hours in downstream and 6 hours in upstream. Also, speed of the stream is given 1 km/hr.
We have to find the speed of the streamer in still water.
_____...
Let the speed of the streamer in still water be = x km/hr
(Distance = Constant)
Downstream:-
Time taken = 5 hr
Speed of the streamer = 1 km/hr
Thus, overall speed in this case = (x + 1) km/hr
(In downstream)
Since,
Distance = (Speed)(Time)
Therefore,
Distance = 5(x + 1) km
Upstream:-
Time taken = 6 hr
Speed of the streamer = 1 km/hr
Thus, overall speed in this case = (x - 1) km/hr
(In upstream)
Thus,
Distance = 6(x - 1) km
We have discussed earlier that distance will remain constant,
Therefore,
5(x + 1) = 6(x - 1)
→ 5x + 5 = 6x - 6
→ 5x - 6x = - 6 - 5
→ - x = - 11
→ x = 11 km/hr. (Answer).
Now, check if the LHS is equal to RHS or not. By my calculation, it is showing 60 km in both the sides. Put the value of (x) in equation.
x = 11 km/hr
the speed of the streamer in still water = x km/hr
the speed of the stream is 1 km/hr
⟹ Speed downstream = x + 1 km/hr
⟹ Time taken = 5 hr
★ Distance = speed × time
Distance = 5 ( x + 1 )
Distance = 5x + 5 ............ (1)
⟹ Speed upstream = x − 1 km/hr
⟹ Time taken = 6 hr
★ Distance=speed × time
Distance = 6 ( x − 1 )
Distance = 6x − 6 ............ (2)
From (1) and (2),
➜ 6x − 6 = 5x + 5
➜ 6x − 5x = 5 + 6
➜ 1x = 11
➜ x = 11 / 1
➜ x = 11 km/hr