Question

Hey this is your mademoiselle aishregards
Answer correctly..... =_=
The density of ice is 0.92g/cm3 and that of sea water is 1.025g/cm3. Find the total volume of an iceberg which floats with its volume 800cm3 above water......
Caution...answer with steps....

Answer 1

HEY FRIEND HERE YOUR ANSWER

the ice is floating,so net force is zero.

to get that net force, then

net force= weight of water displaced aweigh of iceberg

net force= 1.025( volume)-.92(800+volume)
solve for volume.

volume=.92*800/(1.025-.92)

I HOPE IT'S HELP YOU

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Answer 2

$\huge \boxed{ \mathfrak{Hello \: Friend }}$

$Your \: Answer \: Is \: \colon -$

According to the principle of floating, an object that floats in a liquid displaces an amount of liquid  equal to the mass of the object.

Therefore, if V is the volume of ice, its mass is V*density of ice = V*0.92gm.

Therefore, the amount of water displaced by the water = V*92gm

$The \: volume \: of \: water \: displaced \: \\ \\ = V \times \frac{0.92}{density \: of \: water} \: \\ \\ = V \times \frac{0.92}{1.025} \: \\ \\ =0.897560975V.$

Therefore, if V is the volume of ice, its mass is V*density of ice = V*0.92gm.

$If \: 800 \: cm^3 \: of \: ice \: is \: above \: water, \\ \: then \: its \: volume \: x \: is \: given \: by:$

$0.102439024:800 cm^3 :: 1: x. So,$

$x= \frac{800}{0.102439024}=7809.52381 cm^3.$

Therefore, the amount of water displaced by the water = V*92gm

$The \: volume \: of \: water \: displaced \: \\ = V \times \frac{0.92}{density of water} \\ \\ = V \times \frac{0.92}{1.025} \\ \\ =0.897560975V.$

Therefore 0.8997560975 of the volume of ice is sunk and (1-0.897560975) of its volume is above water. Or 0.102439024 of its volume is above see water.

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$\mathcal{Hope \: the \: above \: answer \: helped \: you}$

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