Question

Heya Friends!! ♡♥

Please solve it.


Find the value of y in:

$\frac{y + 7}{3} = 1 + \frac{3y - 2}{5}$
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Answer 1

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Answer 2

Step-by-step explanation:

$heloo... \\ \frac{y + 7}{3} = 1 + \frac{3y - 2}{5} \\ \frac{y + 7}{3} = \frac{5 + 3y - 2}{5} \\ \frac{y + 7}{3} = \frac{3y + 3}{5} \\ \\ shifting \: \frac{y + 7}{3} \: on \: other \: side = > \\ \frac{3y + 3}{5} - \frac{y + 7}{3} = 0 \: \\ \\ lcm \: of \: 5 \: and \: 3 \: is \: 15 \\ \frac{3(3y + 7) - 5(y + 7)}{15} = 0\\ \frac{9y + 21 - 5y - 35}{15} = 0\\ \frac{4y - 14}{15} = 0 \\ multiplying \: by \: 15 \: on \: both \: sides = > \\ 15 \frac{4y - 14}{15} = 15(0) \\ 4y - 14 = 0 \\ y = \frac{14}{4} \\ y = \frac{7}{2} = 3.5 \\ \\ hope \: it \: helps \: uh..$