Question

Heya‼️‼️♥️♥️‼️‼️

Solve question in attachment☺️

Sukriya✌️✌️

Answer 1

here is your answer I hope it helps

Answer 2

$Here \: is \: the \: answer \: of \: your \: question$

There are two ways to solve this question.

`$\textbf{First method}$`

6.022 × 10²³ molecules of H2O = 1 mol means 18 g

Mass of 1 molecule of water = 18/6.022 × 10²³

Density = Mass/Volume

V = M/D

V = 18/6.022 × 10²³

= 3 x 10-²³ molecules of H2O

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`$\textbf{Second method}$`

Density of water = 1 g/ml

So, volume occupied by 1 g of water = 1 ml

Now,

Number of moles in water of 1 g = 1/18 moles

Now, 18 g of water contains 6.022 × 10²³ molecules of H2O

So, 1 g of water contains = (6.022 × 10²³) ÷ 18

On dividing we get,0.033 x 10²³ molecules of H2O.

Volume occupied by 0.033 × 10²³ molecules of H2O = 1 ml

So, Volume occupied by 1 H2O molecules will be 1/0.033 × 10²³ ml

On solving we get,

2.98 × 10-²³ molecules of H2O.

By rounding off we get,

= 3 x 10-²³ molecules of H2O