Question

Heya
The question is here
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Answer 1

Heya!

Here is yr answer......

➡ Show that the bisectors of the base angles of a triangle can never enclose a right triangle.

Sol :

Let us take a Δ ABC

Bx is the bisector of angle B and Cy is the bisector of angle C

Here, p is the point formed by the bisectors!

Since, p is greater than 90°.

Therefore, The bisectors of base angles of a triangle can never enclose a right triangle.

HENCE PROVED!

Hope it hlpz..

Answer 2

★Heya !!★

Here's your solution !!!
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☛In ∆ABC, BP and CP are bisectors of angles B and C respectively.

Hence,

∠A + ∠B + ∠C = 180°
∠A + 2∠1 + 2∠2 = 180°
2(∠1 + ∠2) = 180° - ∠A
(∠1 + ∠2) = 90° - (∠A/2) ··········(1)
In ∆PBC, ∠P + ∠1 + ∠2 = 180°
∠P + [90° - (∠A/2) = 180° [From (1) ]
∠P = 180° - [90°-(∠A/2)
[90° + (∠A/2)

Hence, angle P is always greater than 90°.

thus PCB can never be a right angle
triangle.
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