Chemistry, asked by darkfire, 11 months ago

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EXPLAIN----

(1) Methylamine is a stronger base than ammonia.

(2)Primary amines have higher b.p than tertiary amines.

(3)Ethylamine is soluble in water whereas aniline is not soluble in water.

(4)Tertiary amines do not undergo acylation reaction.


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Answers

Answered by ItzSanam126
9

Answer:

(1) Methylamine is a stronger base than ammonia because methyl group is electron releasing and increase electron density on N.

(2)The high boiling point of primary amines is due to intermolecular H-bonding whereas there is no H-bonding in tertiary anines.

(3)Ethylamine is soluble in water due to formation of H-bonding with water but due to bulky phenyl group aniline does not form H-bond and thus is insoluble in water.

(4)It is beacause tertiary amines do not have hydrogen attached to nitrogen.

Answered by mdivya9231
4

1 ) Yes methylamine a stronger base than ammonia since it as a election donating group (methyl). Therefore electron density on Nitrogen atom increase.Hence it is stronger base,whereas in ammonia electron donating group is absent

2 ) In a tertiary amine there aren't any hydrogen atoms attached directly to the nitrogen. That means that hydrogen bonding between tertiary amine molecules is impossible. ... Therefore primary amines have higher boiling point than tertiary amines.

3 )Ethylamine when added to water forms intermolecular H−bonds with water. And therefore it is soluble in water. But aniline does not form H−bond with water to a very large extent due to the presence of a large hydrophobic −C6H5 group. Hence, aniline is insoluble in water.

4 ) Amines containing replaceable hydrogen atom react with acid chloride to form substituted amides. This reaction is called acylation reaction. In case of tertiary amines there is no replaceable H atom and therefore, these do not react with acid chloride and hence do not undergo acylation.

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