Physics, asked by Eshita111, 1 year ago

heyya !! plzz explain !!

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Answered by RajveerShekhawat1

Okay.. Fine...... Now

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Answered by TheEdward

hello there!!
$\frac{v}{ \sqrt{2} }$

as the potential is decreasing and then constant so.. the value of V(rms ) remain unchanged.. as

check out the attachment... :)

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