Question

Hi!❤


11.A 10% solution (by mass) of sucrose in water
has freezing point of 269.15 K. Calculate
the freezing point of 10% glucose in water,
if freezing point of pure water is 273.15 K.
Given : Molar mass of sucrose
=342 g mol
and
Molar mass of glucose = 180 g mol!​

Answer 1

Explanation:

Given:

T1 = 269.15 k

T2 = 273.15 k

Molar mass of sucrose = 342 g mol^-¹

Molar mass of glucose = 180 g mol^-¹

∆Tf = Kf m

Here , m = w2x 1000/ M2XM1

273.15-269.15 = Kf x 10 x1000/ 342 x90

Kf = 12.3 K kg/mol

∆Tf = Kf m

= 12.3 x 10 x1000/ 180x90

= 7.6 K

Tf = 273.15 – 7.6 = 265.55 K