Question

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HI
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A convex lens of focal length 25 cm and a concave lens of focal length 10 cm are placed in close contact with one another a)What is power of this combination b)what is focal length of this combination


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Answer 1

Ello user !!!!!

Here is your answer,

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power = 1/f where f is focal length in meter

now p1 = 100/25= 4 (for convex lens)

p2 = -100/10 = -10(power is negative because focla length of concave lens is negative)

now resultant power = p1+p2 = 4+(-10) = -6D

Focal length =Reciprocal of power = -16.7 cm

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HOPE THIS HELPS YOUU :)

AND STAY BLESSED.

Answer 2

Ello user !!!!!

Here is your answer,

===================================================

power = 1/f where f is focal length in meter

now p1 = 100/25= 4 (for convex lens)

p2 = -100/10 = -10(power is negative because focla length of concave lens is negative)

now resultant power = p1+p2 = 4+(-10) = -6D

Focal length =Reciprocal of power = -16.7 cm

====================================================

HOPE THIS HELPS YOUU :)

AND STAY BLESSED.