Question

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If y(x) is solution of

x. dy/dx + 2y = x^2

y(1) =1 then the value of

y(1/2 ) = ❓❓❓❓


i) -49/16

ii) 49/ 16

iii) 45/8

iv) -45/8


Thanks !!!

complete solution otherwise reported❎❎❎❎❎❎❎​

Answer 1

$\huge\red{Solution}$

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Answer 2

Answer:

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