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Please help me with this :-
Drive displacement-time relation using velocity-time graph .
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ayush579:
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Secondary School
Physics
5 points
Drive graphically the equation for position time relation for an object travelling a distance 's' in time 't' under uniform acceleration.
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See pic, Let a body moves from D to with initial speed u and are moving with uniform acceleration finally body reach point B after time taken t.
distance travelled by body = area between curve v-t
= area DBA + area DAEO
= 1/2 × base × height + length × Breadth
= 1/2 × t × (v - u) + ut
we know , ( v - u ) = at, put it above
= 1/2× t × at + ut
= ut + at²/2
hence , distance travelled by body = ut + 1/2at²
Secondary School
Physics
5 points
Drive graphically the equation for position time relation for an object travelling a distance 's' in time 't' under uniform acceleration.
Ask for details
See pic, Let a body moves from D to with initial speed u and are moving with uniform acceleration finally body reach point B after time taken t.
distance travelled by body = area between curve v-t
= area DBA + area DAEO
= 1/2 × base × height + length × Breadth
= 1/2 × t × (v - u) + ut
we know , ( v - u ) = at, put it above
= 1/2× t × at + ut
= ut + at²/2
hence , distance travelled by body = ut + 1/2at²
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