Question

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todays question

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Answer 1

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Answer 2

Answer:

135.67 m^3

Step-by-step explanation:

radius of cone = 3 m.

Then, diameter = 3/2 m

height of cone h = 7 m.

volume of cone = (1/3)πr²h

                         = (1/3) * π * 3² * 7

                         = (1/3) * (22/7) * 9 * 7

                         = 198/3

                        = 66 m³

Height of frustum = 10.5 - 7 = 3.5 m.

∴ Volume of lower portion,

=> (1/3) * (22/7) * 3.5 * (3² + 2² + 3 * 2)

=> (1/3) * (22/7) * 3.5 * (9 + 4 + 6)

=> (1/3) * (22/7) * 3.5 * 19

=> 1463/21

=> 69.67 m³

Hence,

Volume of haystack = 66 + 69.67 = 135.67 m³

#Hope my answer help you!