Hi mates!
A ball is gently dropped from a height of 20m. If its velocity increases uniformly at the rate of 10 M per second square with what velocity will it strike the ground.After what time will it strike the ground?
Answers
Answered by
13
time =speed/velocity
=20/10
=2.
=20/10
=2.
Answered by
22
Initial velocity of the ball = u = 0
Acceleration = g = 10 m/s²
Distance Covered = s = h = 20 m
Using v²-u² = 2as
v²-0= 2gh = 2×10 ×20 = 400
v² = 400
v = 20 m/s
Using v = u+at
20=0+10t
t = 2 s
Acceleration = g = 10 m/s²
Distance Covered = s = h = 20 m
Using v²-u² = 2as
v²-0= 2gh = 2×10 ×20 = 400
v² = 400
v = 20 m/s
Using v = u+at
20=0+10t
t = 2 s
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