hi please check the question above
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in this figure AP = 10 and AB = 20
in triangle APQ
tan 30 = PQ/ AP
1/√3 = PQ/ 10
PQ = 10/√3
triangle APQ is similar triangle ABC
so PQ/ BC = AP/ AB
10/20 = (10/√3)/ BC
BC = 20/√3
now we can find the volume of frustum that is
π/ 3 * h ( r^2 + R^2 + r*R) = π *R1*R1* h 1
10 / 3 ( 100/3+ 400/3+ 10*20/3) = 1/32*1/32* H1
7000/9 = 1/32 *1/32 * H1
H1 = 796444.44 cm
H1 = 7964.44 m
H1 = 7.964 km
in triangle APQ
tan 30 = PQ/ AP
1/√3 = PQ/ 10
PQ = 10/√3
triangle APQ is similar triangle ABC
so PQ/ BC = AP/ AB
10/20 = (10/√3)/ BC
BC = 20/√3
now we can find the volume of frustum that is
π/ 3 * h ( r^2 + R^2 + r*R) = π *R1*R1* h 1
10 / 3 ( 100/3+ 400/3+ 10*20/3) = 1/32*1/32* H1
7000/9 = 1/32 *1/32 * H1
H1 = 796444.44 cm
H1 = 7964.44 m
H1 = 7.964 km
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nitirocks12pehtmu:
yess
thanks
welcome
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bro i m a teacher , practice hard and you can do good ,all the best
thank you sir.
YOU ARE AMAZING I AM NOT EVEN KIDDING
thanks bro
Yeah you are amazing (bro)
if you need any help you can ask me anytime
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