Question

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Three resistors of 6 ,2 and X ohm are connected in series to a cell of potential difference of 1.5 V and the current flowing in the circuit is 1/6 A
Draw a circuit diagram and calculate the value of X .

pls

Answer 1

by ohms law

R=v/I

R =1.5*6=9

as the resistors are connected in parallel

R=r1+r2+x

9=6+2+x

x=1ohm

pls find circuit diagram in attachment

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