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Given that, diameter(d) of cylinder is 1.4 m and length(h) is 8 m.
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
⇒ the radius of sphere(r) = radius of cylinder
⇒ surface area of tank = surface area of cylinder + 2(surface
Area of hemisphere)
= 2πrh + 2(2πr2)
= 2πr(h + 2r)
= 41.36 m2
⇒ ∴ the cost of painting it on the outside at rate of D20 per m2
= 41.36 × 20
= D827.20
Answered by
0
Hey Mate......
Answer:
External diameter of the cylinder =1.4m
Length of the cylinder=5m
Radius(r)=1.4/2
=0.7m
Height (h)=5m
Curved surface area of the cylinder =2πrh
2*22/7*0.7*5
= 22m²
Area of the base of the tank =πr²
=22/7 *0.7²
=30.8m²
Total outer area to be painted=22+15.4+30.8
=68.2 m²
Cost of painting =20*68.2
=1364.0
Answer:
External diameter of the cylinder =1.4m
Length of the cylinder=5m
Radius(r)=1.4/2
=0.7m
Height (h)=5m
Curved surface area of the cylinder =2πrh
2*22/7*0.7*5
= 22m²
Area of the base of the tank =πr²
=22/7 *0.7²
=30.8m²
Total outer area to be painted=22+15.4+30.8
=68.2 m²
Cost of painting =20*68.2
=1364.0
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