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65.21 m/s
In the absence of any external force, the momentum of the system would remain conserved in this interaction between the club and the ball. Thus, the velocity of the ball can be determined by using the conservation of momentum.
Let m be the mass of the club, and m' be that of the ball. Also, let u and u' be the velocities of the club and the ball before the hit, while v and v' be the velocities after the hit.
Then:
m = 0.2 kg, m' = 0.046 kg, u =55 m/s, u' = 0 (since the ball was at rest before the strike), v = 40 m/s, and v' is to be determined.
Now, applying the conservation of momentum:
mu + m'u' = mv + m'v'
0.2(55) + 0.046(0) = 0.2(40) + 0.046v'
11 = 8 + 0.046v'
v' = 3/0.046
v' = 65.21 m/s
Thus, the velocity of the ball is 65.21 m/s just after the hit.
In the absence of any external force, the momentum of the system would remain conserved in this interaction between the club and the ball. Thus, the velocity of the ball can be determined by using the conservation of momentum.
Let m be the mass of the club, and m' be that of the ball. Also, let u and u' be the velocities of the club and the ball before the hit, while v and v' be the velocities after the hit.
Then:
m = 0.2 kg, m' = 0.046 kg, u =55 m/s, u' = 0 (since the ball was at rest before the strike), v = 40 m/s, and v' is to be determined.
Now, applying the conservation of momentum:
mu + m'u' = mv + m'v'
0.2(55) + 0.046(0) = 0.2(40) + 0.046v'
11 = 8 + 0.046v'
v' = 3/0.046
v' = 65.21 m/s
Thus, the velocity of the ball is 65.21 m/s just after the hit.
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High speed stroboscopic photographs show
65.21 m/s
65.21 m/s
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