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Given data is
Tension in the string, T = 200 N
Mass of the string, M = 2.50 kg
Length of the string, l = 20.0 m
Mass per unit length, µ = M/l = 2.5/20 = 0.125 kg m-1
The velocity (v) of the transverse wave in the string is given by the relation:
v =
v = √200/0.125
= √1600 = 40 m/s
Time taken by the wave to reach the other end, t = l/v = 20/40 = 0.5 s
So, time taken for the disturbance to reach the other end of the string is 0.05 s.
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