hiii guys solve it please♡♡♡♡
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(i) Equating the toraque in both cases:
E¹l¹= E²l²
150×0.4= l²× 60
l²= 150× 0.4/60
(ii) (i) inclined plane is used to multiply forces.
(ii) Pulley is used to change the direction of the force applied
(iii)The diagram shows that load L is in between the effort E and fulcrum F. So this belongs to class 2 lever.
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