hlo guys solve this give answer step-by-step to get a brainlist answer.
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Step-by-step explanation:
put n = 1
=> (1)³ - 6(1)² + 11(1) - 6
=> 12-12 = 0
=> a1=0
=> put n=2
=> (2)³ - 6(2)² + 11(2) -6
=> a2 = 8 - 24 + 22 - 6
=> a2 = 0
=> put n=3
=> a3 = (3)³-6(3)²+11(3)-6
=> a3 = 27 - 54 + 33 - 6
=> a3 = 0
=> now an = n³-6n²+11n-6
=> an = n³ - 3*2n² + 12n - n -8+2
=> an = n³ - 3*2n² + 12n-8 - n+2
=> an = n³ - 3*2n(n-2) - 2³ - n+2
=> an = (n-2)³ - (n-2)
=> when we put n≥3 value will be always positive. hence proved.
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hope it helps you Mark me as brainliest
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