Question

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⇆⇆QUESTION:-

║║║║║║DERIVE THE 3RD EQUATION OF MOTION.║║║║║║║


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Answer 1

Consider the velocity-time graph for a body having some non zero initial velocity at time t = 0.

u: velocity at time t1

v: velocity at time t2

a: uniform acceleration of the body along the straight line

Displacement covered during the time interval t2 - t1 = Area ABt1t2

S = Area of triangle ABA’ + Area of rectangle AA’t2t1 = Area of trapezium

S = ½ x Sum of parallel sides x Perpendicular distance

....... (Equation 1)

From the first equation of motion, v = u + at;

Substituting in equation 1, we get

or, v2 – u2 = 2as

Answer 2

Explanation:

Refer to the attachment...