Math, asked by sohailmumtazshaikh, 9 months ago

Hospitals has 16 isolation rooms. Each room has a patient with with different illness. Patient in room 13 recovers and now say goodbye to each patient and visits only once. If he entered twice in any room he will becomes ill again. How does he do this and exit from room 4?

Answers

Answered by Swarup1998
21

It is said that the patient of room no. 13 is not allowed to enter other rooms more than once. It means that the condition is restricted to other rooms. But room no 13 is his own so he can visit his cell twice or more times if required.

However three possible ways arise.

A. See the first picture.

   13 > 14 > 13 > 9 > 10 > 11 > 15 > 16 > 12 > 8 > 7 > 6 > 5 > 1 > 2 > 3 > 4

B. See the second picture.

   13 > 9 > 13 > 14 > 10 > 11 > 15 > 16 > 12 > 8 > 7 > 6 > 5 > 1 > 2 > 3 > 4

C. See the third picture.

   13 > 9 > 13 > 14 > 10 > 6 > 5 > 1 > 2 > 3 > 7 > 11 > 15 > 16 > 12 > 8 > 4

Read more on Brainly:

  1. A prisoner who died in cell number 13, How to take his body out of the prison through Gate 4. the conditions : The body must pass through all the cells for all prisoners to see. No prisoner (bold for a reason ) is allowed to see him more than once. - https://brainly.in/question/16517949
  2. The person in roon no.13 and wants to go out through 4. He wants to meet his person in each room before going out. Conditon is he cannot enterthe other rooms twice. - https://brainly.in/question/16538581
Attachments:
Answered by nidaeamann
24

Step-by-step explanation:

The solution is that first the person will enter 14 and then will come back to 13. He then goes to 9 from 13, the towards 10 from 9, then to 11, then to 15, then he goes to 16 and then to 12, from 12 he goes to 8 and the in 7, 6 and 5. From room 5 he enters 1 and then roon 2 and then 3 and finally exits from room 4

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