Question

how can -cos²x/-sin²x = cot²x pls anyone explain ​

Answer 1

Answer:

it's an math's formula

Answer 2

Answer:

Step-by-step explanation:

$= \frac{(-cosx )* cosx}{sinx * (-sinx)}$

$+ * - = -$

So now it would be,

$= \frac{-cos^{2}x}{-sin^{2}x}$

Minus Minus will get cancel so it will be

$= \frac{cos^{2}x}{\\sin^{2}x}$

Now we know that,

$\frac{cosx}{sinx} = cotx ---(trignometric-ratio)$

So.

$= \frac{cos^{2}x}{\\sin^{2}x} = cot^{2} x$

Hence Proved.