how can three resistors of resistance 2 ohms 3 years and 6 ohms be connected to give a total resistance of a is equal to 4 ohms and b is equal to 1 Ohm
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Connect the Resistors 3 Ohm and 6 Ohm in parallel and the resulting resisistance is 1/(1/3+1/6) = 18/(6+3) = 2 Ohm . Let A and beB be the terminals to which they are connected. Let the resistor 2 Ohm be connected in series to this 3Ohm and 6 Ohm parallel group resistors. Now the total resistance of the circuit is 2Ohm+2Ohm= 4 Ohm.
If each of the 2Ohm,3ohm and 6ohm resistorsare connected in parallel, then their net resistance = 1/{1/2+1/3+1/6} Ohm = 6/(3+2+1)Ohm = 1 Ohm.
Hope this helps.
If each of the 2Ohm,3ohm and 6ohm resistorsare connected in parallel, then their net resistance = 1/{1/2+1/3+1/6} Ohm = 6/(3+2+1)Ohm = 1 Ohm.
Hope this helps.
Rajrupa:
thnx
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hey
not correct question check your que.
not correct question check your que.
it is correct
ohkk
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