Question

how can we prepare 500cm of 0.3M kMnO4 solution​

Answer 1

Answer:

4.7M.

Explanation:

C=n/v => n =c. v

nHCL =18M. 19.10-3L

=3.42.moles HCL

3.42 moles

C = ----------------- =4.7M

730.10-3 L

your answer