Question

How do you calculate the shunt required to increase the range and times?
A galvanometer carries as maximum current of 15 mA, when a voltage of 75 mV is applied to it. How to convert this into a voltmeter to read upto 150 volt and into an ammeter to read upto 25 A?

Answer 1

Explanation:

Correct option is C)

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Given: V = 750 × 10-³V;

Ig = 15 x 10-³A and I = 25A

Using, a = Ig

750 × 10-3 15 x 10 -3 = = 50Ω

Ig

S

XI

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S+ a 15 x 10-3 = S x 25

S + 50

S = 0.039

Hope it helps you ❤