How do you evaluate the expression 7p+q(3+r),for p=3,q=2,and r=1?
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Solution:
Given p = 3 , q = 2 and r = 1
Now ,
value of 7p+q(3+r)
= 7×3 + 2(3+1)
= 21+2×4
= 21 + 8
= 28
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